Given the prevalence of HABP2 rs7080536 in the general population, Carvajal-Carmona et al.59 have pointed out that there is “high probability (>10%) that HABP2 G534E will be present in 4 out of 29 families by chance”.59 Applying the Fisher’s exact test of proportions indicates that there is less than a 5% chance that a 1/29 (a 1/58 AF) proportion is different than 4/29. The gene discussed is HABP2; the disease is atrial fibrillation.